Mahesh has given a two-dimensional 3*3 array starting from A [0][0]. You should add the alternate elements of the array and print its sum. It should print two different numbers the first being sum of A 0 0, A 0 2, A 1 1, A 2 0, A 2 2 and A 0 1, A 1 0, A 1 2, A 2 1.

 #include <stdio.h>

int main()

{   int A[3][3],i,j;

    for(i=0;i<3;i++)

    {for(j=0;j<3;j++)

    {scanf("%d ",&A[i][j]);}}

    int m=0,n=0;

    for(i=0;i<3;i++){

    for(j=0;j<3;j++){

    if((i+j)%2==0)

    m=m+A[i][j];

    else

    n=n+A[i][j];}}

    printf("%d\n%d",m,n);

return 0;

}